Pandas 从多列返回值(如果等于另一列中的值) - python

我有一个这样的Pandas数据框:

  A      B        C         D
0 month   month+1 quarter+1 season+1
1 season  month+5 quarter+3 season+2
2 day     month+1 quarter+2 season+1
3 year    month+3 quarter+4 season+2
4 quarter month+2 quarter+1 season+1
5 month   month+4 quarter+1 season+2

我想基于多个IF条件插入一个名为“ E”的新列。如果“ A”列等于“月”,则返回“ B”中的值,如果“ A”列等于“季度”,则返回“ C”中的值,如果“ A”列等于“季节”,则返回“ D”中的值,如果没有,则返回“ A”列中的值

  A      B        C         D        E
0 month   month+1 quarter+1 season+1 month+1
1 season  month+5 quarter+3 season+2 season+2
2 day     month+1 quarter+2 season+1 day
3 year    month+3 quarter+4 season+2 year
4 quarter month+2 quarter+1 season+1 quarter+1
5 month   month+4 quarter+1 season+2 month+4

我在执行此操作时遇到了麻烦。我试着玩一个函数,但是没有用。看看我的尝试:

def f(row):
    if row['A'] == 'month':
        val = ['B']
    elif row['A'] == 'quarter':
        val = ['C']
    elif row['A'] == 'season':
        val = ['D']
    else:
        val = ['A']
    return val

df['E'] = df.apply(f, axis=1)

编辑:将最后一个else更改为“ A”列

参考方案

只需使用np.select

c1 = df['A'] == 'month'
c2 = df['A'] == 'quarter'
c3 = df['A'] == 'season'

df['E'] = np.select([c1, c2, c3], [df['B'], df['C'], df['D']], df['A'])

Out[271]:
         A        B          C         D          E
0    month  month+1  quarter+1  season+1    month+1
1   season  month+5  quarter+3  season+2   season+2
2      day  month+1  quarter+2  season+1        day
3     year  month+3  quarter+4  season+2       year
4  quarter  month+2  quarter+1  season+1  quarter+1
5    month  month+4  quarter+1  season+2    month+4

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