我使用一个功能键来引用我的父对象中的另一个对象。但是,当我转到django admin创建的下拉列表时,我得到的是对象名称而不是字段值。如何将字段值添加到表单?
管理员
from django.contrib import admin
from .models import Maintenance
from .models import MaintenanceType
from .models import ServiceType
# Register your models here.
class MaintenanceAdmin(admin.ModelAdmin):
list_display = ('Title','Impact','Service','Description','StartTime','EndTime',)
list_editable = ('Title','Impact','Service','Description','StartTime','EndTime',)
admin.site.register(Maintenance, MaintenanceAdmin)
class MaintenanceTypeAdmin(admin.ModelAdmin):
list_display = ('Type',)
list_editable = ('Type',)
admin.site.register(MaintenanceType, MaintenanceTypeAdmin)
class ServiceTypeAdmin(admin.ModelAdmin):
list_display = ('Service','Service',)
list_editable = ('Service','Service',)
admin.site.register(ServiceType, ServiceTypeAdmin)
models.py
from django.db import models
# Create your models here.
class MaintenanceType(models.Model):
Type = models.CharField(max_length=200)
class Meta:
verbose_name = "Planned Maintenance Types"
verbose_name_plural = "Planned Maintenance Types"
class ServiceType(models.Model):
Service = models.CharField(max_length=200)
class Meta:
verbose_name = "Service Types"
verbose_name_plural = "Service Types"
class Maintenance(models.Model):
Title = models.CharField(max_length=200)
Impact = models.ForeignKey(MaintenanceType)
Service = models.ForeignKey(ServiceType)
Description = models.TextField()
StartTime = models.DateTimeField()
EndTime = models.DateTimeField()
class Meta:
verbose_name = "Planned IT Maintenance"
verbose_name_plural = "Planned IT Maintenance"
参考方案
在__str__
模型中实现MaintenanceType
,该模型应以您希望在下拉菜单(以及其他位置)中显示的任何格式返回字符串。
看来您只需要return self.Type
即可。
我正在尝试使用以下代码在django / python中处理表单。home.html:<form action="{% url 'home:submit' %}"method='post'> views.py:def submit(request): a = request.POST([…
在返回'Response'(Python)中传递多个参数 - python我在Angular工作,正在使用Http请求和响应。是否可以在“响应”中发送多个参数。角度文件:this.http.get("api/agent/applicationaware").subscribe((data:any)... python文件:def get(request): ... return Response(seriali…
Python exchangelib在子文件夹中读取邮件 - python我想从Outlook邮箱的子文件夹中读取邮件。Inbox ├──myfolder 我可以使用account.inbox.all()阅读收件箱,但我想阅读myfolder中的邮件我尝试了此页面folder部分中的内容,但无法正确完成https://pypi.python.org/pypi/exchangelib/ 参考方案 您需要首先掌握Folder的myfo…
python JSON对象必须是str,bytes或bytearray,而不是'dict - python在Python 3中,要加载以前保存的json,如下所示:json.dumps(dictionary)输出是这样的{"('Hello',)": 6, "('Hi',)": 5}当我使用json.loads({"('Hello',)": 6,…
'ManyToManyDescriptor'类型的参数不可迭代 - python我有模式:class Subscribe(models.Model): class Meta: verbose_name_plural = 'sunscribes' id=models.AutoField(primary_key=True) name=models.CharField(max_length=30,null=False); …