我有一个DeleteView
,用于从模型中删除对象。通过表格中的按钮启动。它工作正常。
class DeleteAssignment(DeleteView):
model = Assignment
success_url = reverse_lazy('company')
我只想让它返回成功的父级观点。我目前将其重定向到父级的父级(company
),因为此视图不需要变量。这很简单,但是父视图需要变量farm_id
进行呈现,这是从网址中捕获的,例如“ / farm / 18”
url(r'^farm/(?P<farm_id>.+)', views.farm, name='farm'),
我已经通过将页面重定向到带有变量farm
的视图farm_id
来解决了页面上的表单。
return redirect(farm, farm_id=farm_id)
如何为我的success_url
用DeleteView
做到这一点?
昵称示例:
views.py
@login_required
def farm(request, farm_id=None):
user = request.user
company_id = user.profile.company_id
farm_id = farm_id
farm_filter = Farm.objects.filter(farm=farm_id)
farm_current = farm_filter[0]
# farm_company =
serial_filter = Sensor.objects.filter(assignment__farm__company_id__isnull=True)
assignment_filter = Assignment.objects.filter(farm=farm_id)
farm_instance = Farm.objects.get(farm=farm_filter[0].farm)
update_farm_form = UpdateFarmForm(instance=farm_instance)
assign_sensor_form = AssignmentForm()
if request.method == 'POST' and 'updatefarm' in request.POST:
update_farm_form = UpdateFarmForm(request.POST, instance=farm_instance)
if update_farm_form.is_valid():
update_farm_form.save()
return redirect(farm, farm_id=farm_id)
else:
if request.method == "POST" and 'assignsensor' in request.POST:
assign_sensor_form = AssignmentForm(request.POST)
if assign_sensor_form.is_valid():
assignment = assign_sensor_form.save()
if user.is_staff is True:
assignment.company_id = farm_filter[0].company_id
else:
assignment.company_id = user.profile.company_id
assignment.save()
return redirect(farm, farm_id=farm_id)
else:
assign_sensor_form = AssignmentForm(request.POST)
return render(request, 'users/farm_template.html', {'company_id': company_id, 'farm_filter': farm_filter, 'farm_current': farm_current, 'serial_filter': serial_filter, 'assignment_filter': assignment_filter, 'update_farm_form': update_farm_form, 'assign_sensor_form': assign_sensor_form})
urls.py
from django.conf.urls import url, include
from django.contrib.auth import views as auth_views
from apps.dashboard import views
from apps.dashboard.views import DeleteAssignment, DeleteFarm
urlpatterns = [
url(r'^company/', views.company_view, name='company'),
# url(r'^test/', views.test),
# url(r'^test2/', views.test2, name='test2'),
# url(r'^farms/', views.add_farms),
url(r'^manual-signup/', views.signup_manual),
url(r'^signup/(?P<company_id>.+)', views.signup_company),
url(r'^settings/', views.update_profile),
url(r'^create-company/', views.create_company),
url(r'^create-sensor/', views.create_sensor),
url(r'^assign-sensor/', views.assign_sensor),
url(r'^login/$', auth_views.login, {'template_name': 'login.html'}, name='login'),
url(r'^logout/$', auth_views.logout, {'next_page': '/login'}, name='logout'),
url(r'^$', views.main),
# url(r'^company/(?P<company_id>.+)/farm/(?P<farm_id>.+)', views.farm),
url(r'^farm/(?P<farm_id>.+)', views.farm, name='farm'),
url(r'^unit/(?P<sensor_id>.+)', views.unit),
# url(r'^company/(?P<company_id>.+)', views.company),
url(r'^download/', views.download),
# url(r'^export/xls/$', views.export_users_xls),
url(r'^live/', views.live),
url(r'^data/', views.data),
url(r'^debug/', views.debug),
url(r'^delete-assignment/(?P<pk>\d+)/$', DeleteAssignment.as_view(), name='delete-assignment', ),
url(r'^delete-farm/(?P<pk>\d+)/$', DeleteFarm.as_view(), name='delete-farm', ),
url(r'^', include('django.contrib.auth.urls'))
]
成功提交表单后,视图即会重定向到自身。这将根据用户提交的内容重新加载表,而无需立即处理js。
farm_id
中的return redirect(farm, farm_id=farm_id)
是通过urls.py url(r'^farm/(?P<farm_id>.+)', views.farm, name='farm'),
中的相应行从URL中捕获的
这就是我要对删除视图所做的全部操作,而不是将成功URL仅仅是一个视图,而是一个具有变量的视图,就像我上面所做的那样。
参考方案
是的,您可以通过success_url
通过以下方式执行此操作:
class DeleteAssignment(DeleteView):
. . . . .
. . . . .
. . . . .
def get_success_url(self):
# if you are passing 'pk' from 'urls' to 'DeleteView' for company
# capture that 'pk' as companyid and pass it to 'reverse_lazy()' function
companyid=self.kwargs['pk']
return reverse_lazy('company', kwargs={'pk': companyid})
这应该工作完美。
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