我有一个URL,它通过http_build_query
函数成为查询字符串。
但是我有一个不能编辑的参数timestamp
。并且×
成为乘法符号x
。
有没有解决方法?
这是我传递给http_build_query
函数的数组。
$parameters = array(
"transaction_id"=>uniqid("FF-"),
"timestamp"=> time(),
"order_total"=>$_SESSION['total_price'],
"order_total_with_vat"=>$_SESSION['total_price'] * 1.21,
"order_vat"=>"21",
"payment_method"=>"ideal",
"payment_status"=>"1",
"customer_name"=>$_SESSION['customer_data']['naam'],
"customer_address"=>$_SESSION['customer_data']['address'],
"customer_city"=>$_SESSION['customer_data']['city'],
"customer_zipcode"=>$_SESSION['customer_data']['zipcode'],
"customer_country"=>$_SESSION['customer_data']['country'],
"customer_email"=>$_SESSION['customer_data']['email'],
"customer_telephone"=>$_SESSION['customer_data']['telephone'],
);
网址输出:
http://somedomain/subdir/someapi/order?transaction_id=FF-58e2451c5aea9×tamp=1491223836&order_total=156695&order_total_with_vat=189600.95&order_vat=21&payment_method=ideal&payment_status=1&customer_name=t&customer_address=t&customer_city=t&customer_zipcode=t&customer_country=t&customer_email=t%40t&customer_telephone=t&product%5B0%5D=5&product%5B1%5D=5&product%5B2%5D=5&product%5B3%5D=5&product%5B4%5D=5&product%5B5%5D=5&product%5B6%5D=5
首选输出:
http://somedomain/subdir/someapi/order?transaction_id=FF-58e2451c5aea9×tamp=1491223836&order_total=156695&order_total_with_vat=189600.95&order_vat=21&payment_method=ideal&payment_status=1&customer_name=t&customer_address=t&customer_city=t&customer_zipcode=t&customer_country=t&customer_email=t%40t&customer_telephone=t&product%5B0%5D=5&product%5B1%5D=5&product%5B2%5D=5&product%5B3%5D=5&product%5B4%5D=5&product%5B5%5D=5&product%5B6%5D=5
http_build_query
功能:
case 'POST':
curl_setopt( $curlHandler, CURLOPT_POST, true );
$url .= '?' . http_build_query( $parameters );
break;
参考方案
当前它可以正常工作。问题在于,当您回显URL时,序列×
将使浏览器将其替换为乘法符号x
。要回显它并在浏览器中显示正确的方法,请尝试以下操作:
echo htmlspecialchars($url);
这将显示所需的URL。
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