使用熊猫删除重复项,但不能正确删除重复项 - python

首先,我不确定是否是drop_duplicates()错误。

我想做的事:
从csv导入文件,对每行执行re.search,如果匹配,则将该行保留在字典中;如果不匹配,则将该行保留在另一字典中。用字典值的长度制作一个图表。

问题
我在csv中有1000行,但结果返回1200。

我的密码

import pandas as pd
import re

# import data
filename = 'sample.csv'

# save data as data
data = pd.read_csv(filename, encoding='utf-8')

# create new dictionary for word that is true and false 
# but doesn't have the keyword in items
wordNT = {}
wordNF = {}
kaiT = {}
kaiF = {}

# if text is True
def word_in_text(word,text,label):
    match = re.search(word,text)

    if match and label == True:
        kaiT.setdefault('text', []).append(text)
    elif match and label == False:
        kaiF.setdefault('text', []).append(text)
    elif label == True and not match:
        wordNT.setdefault('text', []).append(text)
    elif label == False and not match:
        wordNF.setdefault('text', []).append(text)

# iterate every text in data
for index, row in data.iterrows():
    word_in_text('foo', row['text'], row['label'])
    word_in_text('bar', row['text'], row['label'])

# make pandas data frame out of dict
wordTDf = pd.DataFrame.from_dict(wordNT)
wordFDf = pd.DataFrame.from_dict(wordNF)
kaiTDf = pd.DataFrame.from_dict(kaiT)
kaiFDf = pd.DataFrame.from_dict(kaiF)

# drop duplicates
wordTDf = wordTDf.drop_duplicates()
wordFDf = wordFDf.drop_duplicates()
kaiTDf = kaiTDf.drop_duplicates()
kaiFDf = kaiFDf.drop_duplicates()

# count how many 
wordTrueCount = len(wordTDf.index)
wordFalseCount = len(wordFDf.index)
kaiTrueCount = len(kaiTDf.index)
kaiFalseCount = len(kaiFDf.index)

print(wordTrueCount + wordFalseCount + kaiTrueCount + kaiFalseCount)

当我删除线

word_in_text('bar', row['text'], row['label'])

并且只保留

word_in_text('foo', row['text'], row['label'])

print(wordTrueCount + wordFalseCount + kaiTrueCount + kaiFalseCount) 正确返回1000,反之亦然。
但是,当我不这样做时,当它应该仅为1000时,它将返回1200?

CSV INPUT示例
文字,标签
“嘿”,TRUE
“晕”,假
“你好吗?”,是

预期的输出
1000

输出值
1200

参考方案

在功能word_in_text中,更新四个字典:wordNTwordNFkaiTkaiF

然后在迭代数据帧时调用word_in_text两次:

# iterate every text in data
for index, row in data.iterrows():
    word_in_text('foo', row['text'], row['label'])
    word_in_text('bar', row['text'], row['label'])

因此,搜索结果是'foo'的结果和'bar'的结果的混合。

相反,您应该在开始新搜索之前清理这四个字典:

def search(text):
    wordNT = {}
    wordNF = {}
    kaiT = {}
    kaiF = {}

    # iterate every text in data
    for index, row in data.iterrows():
        word_in_text(text, row['text'], row['label'])

    # make pandas data frame out of dict
    wordTDf = pd.DataFrame.from_dict(wordNT)
    wordFDf = pd.DataFrame.from_dict(wordNF)
    kaiTDf = pd.DataFrame.from_dict(kaiT)
    kaiFDf = pd.DataFrame.from_dict(kaiF)

    # drop duplicates
    wordTDf = wordTDf.drop_duplicates()
    wordFDf = wordFDf.drop_duplicates()
    kaiTDf = kaiTDf.drop_duplicates()
    kaiFDf = kaiFDf.drop_duplicates()

    # count how many 
    wordTrueCount = len(wordTDf.index)
    wordFalseCount = len(wordFDf.index)
    kaiTrueCount = len(kaiTDf.index)
    kaiFalseCount = len(kaiFDf.index)

    print(wordTrueCount + wordFalseCount + kaiTrueCount + kaiFalseCount)

search('foo')
search('bar')

在返回'Response'(Python)中传递多个参数 - python

我在Angular工作,正在使用Http请求和响应。是否可以在“响应”中发送多个参数。角度文件:this.http.get("api/agent/applicationaware").subscribe((data:any)... python文件:def get(request): ... return Response(seriali…

Python exchangelib在子文件夹中读取邮件 - python

我想从Outlook邮箱的子文件夹中读取邮件。Inbox ├──myfolder 我可以使用account.inbox.all()阅读收件箱,但我想阅读myfolder中的邮件我尝试了此页面folder部分中的内容,但无法正确完成https://pypi.python.org/pypi/exchangelib/ 参考方案 您需要首先掌握Folder的myfo…

R'relaimpo'软件包的Python端口 - python

我需要计算Lindeman-Merenda-Gold(LMG)分数,以进行回归分析。我发现R语言的relaimpo包下有该文件。不幸的是,我对R没有任何经验。我检查了互联网,但找不到。这个程序包有python端口吗?如果不存在,是否可以通过python使用该包? python参考方案 最近,我遇到了pingouin库。

Python ThreadPoolExecutor抑制异常 - python

from concurrent.futures import ThreadPoolExecutor, wait, ALL_COMPLETED def div_zero(x): print('In div_zero') return x / 0 with ThreadPoolExecutor(max_workers=4) as execut…

如何用'-'解析字符串到节点js本地脚本? - python

我正在使用本地节点js脚本来处理字符串。我陷入了将'-'字符串解析为本地节点js脚本的问题。render.js:#! /usr/bin/env -S node -r esm let argv = require('yargs') .usage('$0 [string]') .argv; console.log(argv…