因此,在我的程序中,用户一次输入一个数字列表,当我用设置为-1的“ end”语句结束列表数字时,一旦得到,我就得到了平均值和最大值,最小,我的问题是,当我确实获得最小输出时,每次都会为-1,我很难从数组中删除-1,有什么想法吗???
import java.util.Scanner; //import scanner to user scanner tool
public class Average { //creating public class
public static void main(String[]args) { //creating public static main
Scanner input = new Scanner(System.in); //creating scanner input to grab user input
System.out.println("Please enter a list of numbers, entering -1 to end the list: ");
double[] numbers = new double[20]; //creating 20 count array
double sum = 0;
int count = 0;
double average;
int end = -1;
for(int i = 0; i<numbers.length; i++) {
System.out.print("Enter a number: ");
numbers[i] = input.nextDouble();
if(numbers[i]== end) {
break;
}
sum+= numbers[i];
count++;
}
// gets average from user input of numbers
average = sum/count;
System.out.println("Average is: " + average);
double max = maxim(numbers);
System.out.println("Max: " + max);
double min = minim(numbers);
System.out.println("Min: " + min);
}
//method for finding out maximum number from user input
public static double maxim(double[] array) {
double maxNum = array[0];
for(int i = 1; i<array.length; i++) {
if(array[i] > maxNum) {
maxNum = array[i];
}
}
return maxNum;
}
//method for finding out minimum number from user input
public static double minim(double[] array) {
double minNum = array[0];
for(int i = 1; i<array.length; i++) {
if(array[i] < minNum && array[i]!=-1) {
minNum = array[i];
}
}
return minNum;
}
}
参考方案
您需要对负责从用于计算统计信息的代码中读取用户输入的部分代码进行耦合。对于从结果数组中删除-1,您只需要简单地不要将此值放在结果中即可。当用户输入随机数时,首先检查它是否不是-1,然后将其放入结果中。像这样:
import java.util.Scanner;
public class Average {
public static void main(String[]args) { //creating public static main
double[] numbers = readInputNumbers();
System.out.println("Average is: " + average(numbers));
System.out.println("Max: " + max(numbers));
System.out.println("Min: " + min(numbers));
}
public double[] readInputNumbers() {
Scanner input = new Scanner(System.in); //creating scanner input to grab user input
System.out.println("Please enter a list of numbers, entering -1 to end the list: ");
double[] numbers = new double[20];
final int endInput = -1;
for(int i = 0; i < numbers.length; i++) {
System.out.print("Enter a number: ");
double nextNumber = input.nextDouble();
if(nextNumber == endInput) {
break;
} else {
numbers[i] = nextNumber;
}
}
return numbers;
}
public static double max(double[] array) {
double maxNum = array[0];
for(int i = 1; i<array.length; i++) {
if(array[i] > maxNum) {
maxNum = array[i];
}
}
return maxNum;
}
public static double min(double[] array) {
double minNum = array[0];
for(int i = 1; i<array.length; i++) {
if(array[i] < minNum && array[i]!=-1) {
minNum = array[i];
}
}
return minNum;
}
public static double average(double[] numbers) {
double sum = 0;
for(int i = 0; i < numbers.length; i++) {
sum = sum + numbers[i];
}
return sum / numbers.length;
}
}
在jdk自8版本起,您可以简化此任务,如下所示:
import java.util.Scanner;
import java.util.stream.*;
public class Average {
public static void main(String[]args) { //creating public static main
double[] numbers = readInputNumbers();
DoubleSummaryStatistics statistics = DoubleStream.of(numbers).summaryStatistics();
System.out.println("Average is: " + statistics.getAverage()));
System.out.println("Max: " + statistics.getMax());
System.out.println("Min: " + statistics.getMin());
}
public double[] readInputNumbers() {
Scanner input = new Scanner(System.in); //creating scanner input to grab user input
System.out.println("Please enter a list of numbers, entering -1 to end the list: ");
double[] numbers = new double[20];
final int endInput = -1;
for(int i = 0; i < numbers.length; i++) {
System.out.print("Enter a number: ");
double nextNumber = input.nextDouble();
if(nextNumber == endInput) {
break;
} else {
numbers[i] = nextNumber;
}
}
return numbers;
}
}
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