我试图根据Java头脑中的教程创建消息源，但在尝试使该选项具有多个消息属性文件时发生了一个错误，错误在下面给出
Exception in thread "main" org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'messageSource' defined in class path resource [spring.xml]: Initialization of bean failed; nested exception is org.springframework.beans.ConversionNotSupportedException: Failed to convert property value of type 'java.util.ArrayList' to required type 'java.lang.String' for property 'basename'; nested exception is java.lang.IllegalStateException: Cannot convert value of type [java.util.ArrayList] to required type [java.lang.String] for property 'basename': no matching editors or conversion strategy found
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:527)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:456)
at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:293)
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:290)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:196)
at org.springframework.context.support.AbstractApplicationContext.initMessageSource(AbstractApplicationContext.java:755)
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:413)
at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:139)
at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:83)
at test.app.main(app.java:20)
Caused by: org.springframework.beans.ConversionNotSupportedException: Failed to convert property value of type 'java.util.ArrayList' to required type 'java.lang.String' for property 'basename'; nested exception is java.lang.IllegalStateException: Cannot convert value of type [java.util.ArrayList] to required type [java.lang.String] for property 'basename': no matching editors or conversion strategy found
at org.springframework.beans.BeanWrapperImpl.convertIfNecessary(BeanWrapperImpl.java:481)
at org.springframework.beans.BeanWrapperImpl.convertForProperty(BeanWrapperImpl.java:518)
at org.springframework.beans.BeanWrapperImpl.convertForProperty(BeanWrapperImpl.java:512)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.convertForProperty(AbstractAutowireCapableBeanFactory.java:1371)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyPropertyValues(AbstractAutowireCapableBeanFactory.java:1330)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1086)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:517)
... 10 more
Caused by: java.lang.IllegalStateException: Cannot convert value of type [java.util.ArrayList] to required type [java.lang.String] for property 'basename': no matching editors or conversion strategy found
at org.springframework.beans.TypeConverterDelegate.convertIfNecessary(TypeConverterDelegate.java:233)
at org.springframework.beans.BeanWrapperImpl.convertIfNecessary(BeanWrapperImpl.java:466)
spring.xml文件在下面给出
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd" xmlns:context="http://www.springframework.org/schema/context">
<bean id="messageSource" class="org.springframework.context.support.ResourceBundleMessageSource">
<property name="basename">
<list>
<value>mymessages</value>
</list>
</property>
</bean>
<context:annotation-config/>
<context:component-scan base-package="test"/>
当我从上面的代码中删除列表标签时，我能够无例外地运行。空主体在下面给出。
public static void main(String args[]) {
ApplicationContext context = new ClassPathXmlApplicationContext("spring.xml");
System.out.println(context.getMessage("greeting", null, "hiiiii", null));
}
我创建了一个mymessages.prperties文件，其键值对是问候语。请帮助我找到我做错了什么。
参考方案
您正在使用<property name="basename">应该用于单个资源。
但是对于多种资源，您应该使用<property name="basenames">。
您的错误消息明确指出，不能从字符串到列表进行隐蔽。.您正在使用字符串类型，但要传递列表类型..因此，请使用basenames ..
希望能帮助到你...
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