我试图让我的应用程序运行到我的if语句中,但是它归结为else语句,这不是我想要的。回调数据为“ Pass”,这对于我的if条件是正确的,但仍然会失败。请看一下我的代码。
js文件
$http.post(path, postdata
).success(function (data, status, headers, config) {
//if (data) {
// $scope.PostDataResponse = data;
if (data === "Pass"){
setCookie("Username", $scope.formdata.Username);
setCookie("cafe_id", $scope.formdata.cafe_id);
console.log(getCookie("Username"));
alert("ลงทำเบียนสำเร็จ !");
$location.url('/viewSaveCafeDetail');
//console.log(data);
//alert("สมัครสมาชิกสำเร็จ");
//$scope.insertcafe();
//$scope.sendEmail();
// $scope.reset();
// $scope.getData();
}else{ <--- ran down to else statement
alert(data); <--- callback value is "Pass" which is match with my if condition.
}
PHP文件
<?php
header("Access-Control-Allow-Origin: *");
header("Access-Control-Allow-Credentials: true");
header("Access-Control-Allow-Methods : GET,POST,PUT,DELETE,OPTIONS");
header('Access-Control-Allow-Headers: Origin, Content-Type, Accept, Authorization, X-Requested-With, X-YOUR-CUSTOM-HEADER');
header("Content-Type : application/json");
header("Accept : application/json");
$serverName = "localhost";
$userName = "root";
$userPassword = "";
$dbName = "middlework";
$conn = new mysqli($serverName,$userName,$userPassword,$dbName);
mysqli_set_charset($conn,"utf8");
session_unset();
session_start();
$postdata = file_get_contents("php://input");
$request = json_decode($postdata);
$strSQL = "INSERT INTO users ";
$strSQL .="(Username,Password,Firstname,Lastname,Email,Tel,AccountStat,VerifyCode,Verifystat) ";
$strSQL .="VALUES ";
$strSQL .="('".$request->Username."','".$request->Password."','".$request->Firstname."' ";
$strSQL .=",'".$request->Lastname."','".$request->Email."','".$request->Tel."','User','".session_id()."','None' ) ";
mysqli_query($conn,$strSQL) or die(mysqli_error($conn));
$insertcafe = "INSERT INTO cafe (cafe_id,Username,CafeName) VALUES ('1' , '".$request->Username."', '".$request->CafeName."')";
require_once('PHPMailer/PHPMailerAutoload.php');
$mail = new PHPMailer();
$mail->IsHTML(true);
$mail->CharSet = "utf-8";
$mail->IsSMTP();
$mail->SMTPAuth = true; // enable SMTP authentication
$mail->SMTPSecure = "ssl"; // sets the prefix to the servier
$mail->Host = "smtp.gmail.com"; // sets GMAIL as the SMTP server
$mail->Port = 465; // set the SMTP port for the GMAIL server
$mail->Username = "[email protected]"; // GMAIL username
$mail->Password = "1100501068349"; // GMAIL password
$mail->From = "[email protected]"; // "[email protected]";
$mail->FromName = "ThaiCoffeeShopOnline"; // set from Name
$mail->Subject = "ยืนยันการสมัครสมาชิก ThaiCoffeeShopOnline";
$mail->Body = "ขอขอบคุณที่สมัครเป็นสมาชิกกับเรา กรุณาคลิก Url ด้านล่างเพื่อทำการ Activate บัญชีของคุณ</br>
http://localhost/activate.php?sid=".session_id()."&uid=".$request->Username."</br></br> ThaiCoffeeShop.com";
$mail->AddAddress($request->Email); // to Address
if($conn->query($insertcafe))
{
if (!$mail->send()) {
//echo "ไม่สามารถส่ง email: " . $mail->ErrorInfo;
echo "EmailFail";
} else {
echo "Pass ";
//json_decode();
}
//echo "Save Cafe Done.[".$insertcafe."]";
}
else
{
echo "";
//echo mysqli_error($conn);
//echo "ไม่สามาถบันทึกข้อมูล[".$insertcafe."]";
}
$conn->close();
?>
参考方案
您的PHP文件具有echo "Pass ";
,其中写有“ Pass”,后跟一个要与字符串“ Pass”进行比较的空格(不带空格)。
此外,PHP文件的末尾可能还会有一个空白行,该行也将包含在输出中。可以通过从最后删除?>
标记来解决此问题。
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