这是我的代码。
highnum=100
lownum=0
guessnum=highnum/2
print "Please think of a number between 0 and 100!"
while True:
print "Is your secret number is "+str(guessnum)+"?"
print "Enter 'h' to indicate the guess is too high.",
print "Enter 'l' to indicate the guess is too low. ",
print "Enter 'c' to indicate I guessed correctly."
result=raw_input()
if result=="h":
highnum=guessnum
guessnum=int(highnum+lownum)/2
if result=="l":
lownum=guessnum
guessnum=int(highnum+lownum)/2
if result=="c":
break
else:
print "Sorry, I did not understand your input."
print "Game over. Your secret number was: "+str(guessnum)+" ."
每次键入输入内容时,都会打印出“抱歉,我不明白您的输入内容”。条件“其他”不起作用。
我不知道为什么有人可以帮我吗?非常感谢你!
python大神给出的解决方案
因为按照书面规定,每个if
语句都是独立的,所以else
仅对应于您的最后一个if result == 'c'
,因此,如果它们不键入'c'
,则会符合您的else
大小写。
相反,您可以使用if/elif/else
尝试每种情况。
if result=="h":
highnum=guessnum
guessnum=int(highnum+lownum)/2
elif result=="l":
lownum=guessnum
guessnum=int(highnum+lownum)/2
elif result=="c":
break
else:
print "Sorry, I did not understand your input."