我有两个列表['_ru', '_uk', '_en'], ['1','2','3']
我怎么能得到
['1_ru', '1_uk', '1_en', '2_ru', '2_uk', '2_en', '3_ru', '3_uk', '3_en']
在一排?
python大神给出的解决方案
您可以使用itertools.product
来获取两个列表的笛卡尔乘积并将它们联接起来,如下所示
>>> l2, l1 = ['_ru', '_uk', '_en'], ['1','2','3']
>>> from itertools import product
>>> ["".join(items) for items in product(l1, l2)]
['1_ru', '1_uk', '1_en', '2_ru', '2_uk', '2_en', '3_ru', '3_uk', '3_en']
或一行,具有列表理解
>>> ["{}{}".format(i1, i2) for i1 in l1 for i2 in l2]
['1_ru', '1_uk', '1_en', '2_ru', '2_uk', '2_en', '3_ru', '3_uk', '3_en']
这基本上与为第一个列表中的每个项目迭代第二个列表并累积结果相同,就像这样
>>> result = []
>>> for i1 in l1:
... for i2 in l2:
... result.append("{}{}".format(i1, i2))
>>> result
['1_ru', '1_uk', '1_en', '2_ru', '2_uk', '2_en', '3_ru', '3_uk', '3_en']