Python:获取两个点分数字之间的范围 - python

我正在尝试获取两个点分数字之间的数字范围，例如2.1.0和2.1.3。

我的要求是前两个数字必须相同(因此不是2.1.0到2.2.0)

我要出去的是:

['2.1.0', '2.1.1', '2.1.2', '2.1.3']

这是我尝试过的方法，它可以工作，但是我想知道是否有更好的方法可以做到。

start = "2.1.0"
end = "2.1.3"

def get_dotted_range(start,end):
    start_parts = start.split(".")
    end_parts = end.split(".")
    # ensure the versions have the same number of dotted sections
    if len(start_parts) != len(end_parts):
        return False
    # ensure first 2 numbers are the same
    for i in range(0,len(start_parts[:-1])):
        if start_parts[i] != end_parts[i]:
            # part is different betwen start and end!
            return False
    new_parts = []
    # ensure last digit end is higher than start
    if int(end_parts[-1]) >= int(start_parts[-1]):
        # append the version to the return list
        for i in range(int(start_parts[-1]),int(end_parts[-1]) + 1):
            new_parts.append("%s.%s.%s" % (start_parts[0],start_parts[1],i))
    else:
        return False    # end is lower than start

    return new_parts

python大神给出的解决方案

start = "2.1.0"
end   = "2.1.3"

def get_dotted_range(start, end):
    # break into number-pieces
    start = start.split(".")
    end   = end  .split(".")
    # remove last number from each
    x = int(start.pop())
    y = int(end  .pop())
    # make sure start and end have the same number of sections
    #   and all but the last number is the same
    if start != end:
        return []
    else:
        head = ".".join(start) + "."
        return [head + str(i) for i in range(x, y + 1)]

然后

In [67]: get_dotted_range(start, end)
Out[67]: ['2.1.0', '2.1.1', '2.1.2', '2.1.3']