使用列表中的值检查字符串中的字母和数字序列(Python) - python

我一直在搜索字符串以查找数字和字母的特定序列。我需要能够在一个字符串(汽车规则号牌)中搜索两个字母，两个数字然后三个字母的序列。到目前为止，我有这个:

if any(letters in carReg for letters in letters): # Good enough
    print("")
    valid+=1
    if any(numbers in carReg for numbers in numbers): # Good enough
        valid+=1

if valid==0:
    print("Invalid license plate.")
elif valid==1:
    print("Does not contain both numbers AND letters")
elif valid==2:
    print("Valid License Plate")

其中letters和numbers只是列表:

letters = ["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"]
numbers = ["1","2","3","4","5","6","7","8","9","0"]

在程序开始时声明。

上面的代码有效，但前提是输入的字符串完全由字母或数字组成。它不检查序列，而程序需要这样做。

编辑:carReg由以下行给出:

carReg = input("Please enter your licence plate: ")
carReg = carReg.upper()

python大神给出的解决方案

reg = "ab11foo"

a,b,c = reg[:2],reg[2:4],reg[4:] # slice string into ll nn lll
# check a is all alpha characters, b is made up of 0123456789 and c is again alpha and length is correct
if all((a.isalpha(), b.isdigit(), c.isalpha(), len(c)== 3)):
       print("Valid reg")
else:
     print("Invalid reg")

您还可以使用集合和set.issuperset:

letters = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"}
numbers = {"1","2","3","4","5","6","7","8","9","0"}
a,b,c = reg[:2], reg[2:4],reg[4:]

if all((letters.issuperset(a), numbers.issuperset(b), letters.issuperset(c), len(c)==3 )):
    .....